Question

# If one zero of $$2x^{2}-3x+k$$ is reciproal to the other, then find the value of $$k$$.

Solution

## We have, $$2{{x}^{2}}-3x+k=0$$ and one zero is reciprocal to the other. Let one zero $$=x$$ then other zero $$=\dfrac{1}{x}$$ We know that, $$x\times \dfrac{1}{x}=\dfrac{\text{constant}\,term}{cofficent\,\,of\,\,{{x}^{2}}}$$ $$1=\dfrac{k}{2}$$ $$k=2$$ Hence, this is the answer.  Maths

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