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Question

If one zero of $$2x^{2}-3x+k$$ is reciproal to the other, then find the value of $$k$$.


Solution

We have,

$$2{{x}^{2}}-3x+k=0$$

and one zero is reciprocal to the other.

Let one zero $$=x$$ then other zero $$=\dfrac{1}{x}$$


We know that,

$$ x\times \dfrac{1}{x}=\dfrac{\text{constant}\,term}{cofficent\,\,of\,\,{{x}^{2}}} $$

$$ 1=\dfrac{k}{2} $$

$$ k=2 $$


Hence, this is the answer.  

Maths

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