If optical rotation produced by the compound A is -52- the one produced by compound B is-AB

The correct option is B 52^∘ Since (A) and (B) are enantiomers, so specific rotation of B is 52^∘ (because enantiomers have equal and opposite specific rotat ...

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Standard XII

Chemistry

Enantiomers

If optical ro...

Question

If optical rotation produced by the compound (A) is $+ 52^{\circ}$ , the one produced by compound (B) is:

$- 52^{\circ}$

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$+ 52^{\circ}$

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$0^{\circ}$

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Unpredictable

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Solution

The correct option is A
$- 52^{\circ}$

Since (A) and (B) are enantiomers, so specific rotation of B is $- 52^{\circ}$ (because enantiomers have equal and opposite specific rotation).

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If optical rotation produced by the compound (A) is +52∘, the one produced by compound (B) is:

The correct option is A −52∘ Since (A) and (B) are enantiomers, so specific rotation of B is −52∘ (because enantiomers have equal and opposite specific rotation).

If optical rotation produced by the compound (A) is $+ 52^{\circ}$ , the one produced by compound (B) is:

The correct option is A
$- 52^{\circ}$

Since (A) and (B) are enantiomers, so specific rotation of B is $- 52^{\circ}$ (because enantiomers have equal and opposite specific rotation).