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Question

If  |a+b|=|ab|, then which of the following options is correct? 
  1. a||b
  2. ab
  3. aandbare antiparallel
  4. aandbare inclined at angle of 60


Solution

The correct option is B ab
We have|a×b|2=(a+b).(a+b)
           =a.a+a.b+b.a+b.b
          =a2+b2+2a.b
Similarly, 
 |ab|2=(ab).(ab)
=a2+b22a.b
If |a+b|=|ab|
a2+b2+2a.b=a2+b22a.b
a.b=0ab

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