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Question

If a,b,c be any three non - coplanar vectors, then calculate the value of [a+b b+c c+a] is

A
2[a+b+c]
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B
2[a b c]
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C
2[a+b+c]
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D
[a+b+c]
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Solution

The correct option is B 2[a b c]
[a+b b+c c+a]=(a+b).{(b+c)×(c+a)}
=(a+b).(b×c+b×a+c×c+c×a)
=(a+b).(b×c+b×a+c×a)
=a(b×c)+a(b×a)+a.(c×a)+b.(b×c)+b(b×a)+b.(c×a)
=[a b c]+[b c a]
=2[a b c]

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