If $p = 2^{a} \times 3^{b} \times 5^{c}$ and $a > b > c$ are natural numbers, then what is the unit digit of $p$ ?

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Solution

The correct option is A
0

Since a,b,c are natural numbers and $a > b > c$ , none of a,b,c are zero.

So, p has 2, 3, 5 as its fact

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