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Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
If P=6A-tan6A...
Question
If
P
=
sec
6
A
−
tan
6
A
and
Q
=
3
sec
2
A
tan
2
A
,
then
P
−
Q
is equal to
A
0
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B
1
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C
2
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D
−
1
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Solution
The correct option is
B
1
P
−
Q
=
sec
6
A
−
tan
6
A
−
3
sec
2
A
tan
2
A
=
(
sec
2
A
)
3
−
(
tan
2
A
)
3
−
3
sec
2
A
tan
2
A
(
sec
2
A
−
tan
2
A
)
=
(
sec
2
A
−
tan
2
A
)
3
=
1
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0
Similar questions
Q.
If
P
=
sec
6
A
−
tan
6
A
and
Q
=
3
sec
2
A
tan
2
A
,
then
P
−
Q
is equal to
Q.
Prove that:
s
e
c
6
A
−
tan
6
A
=
1
+
3
tan
2
A
+
3
tan
4
A
Q.
Let
P
and
Q
be
3
×
3
matrices with
P
≠
Q
. If
P
3
=
Q
3
and
P
2
Q
=
Q
2
P
, then the determinant of
(
P
2
+
Q
2
)
is equal to
Q.
Let
P
and
Q
be two sets then what is
(
P
∩
Q
′
)
∪
(
P
∪
Q
)
′
equal to ?
Q.
Let
P
and
Q
be
3
×
3
matrices with
P
≠
Q
. If
P
3
=
Q
3
and
P
2
Q
=
Q
2
P
, then determinant of
(
P
2
+
Q
2
)
is equal to:
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Standard XII Mathematics
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