If Pauli's exclusion principle was not known, the electronic configuration of Lithium atom would be:

1 s^{2} 2 s^{1}

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1 s^{1} 2 s^{2}

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1 s^{3}

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1 s^{1} 2 s^{1} 2 p^{1}

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Solution

The correct option is C $1 s^{3}$
According to Pauli's exclusion principle, an orbital can accommodate a maximum of two electrons only. If this rule is violated that means we can have more than two electrons in an orbital.
Now, Li has the atomic number of 3 hence its electronic configuration would become $1 s^{3}$ .

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Q. If the nitrogen atom had an electronic configuration of

1 s^{7}

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1 s^{7}

is not observed because it violates:

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, it would have energy lower than it’s normal ground state configuration of

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is not observed as it violates:

Assuming that the Pauli exclusion principle is non-existent, which of the following will be the most acceptable configuration of Li in the ground state?

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