CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If polynomial= 2x3+3x22x , Divisor= x1 and quotient = 2x2+5x+3, what is the remainder ?


A

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

3


We have formula:

Polynomial=Divisor×Quotient+Remainder

2x3+3x22x=(x1)×(2x2+5x+3)+Remainder

2x3+3x22x=2x3+3x22x3+Remainder

2x3+3x22x2x33x2+2x+3=Remainder

Remainder=3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factor, Remainder and Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon