CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If possible, using elementary row transformations, find the inverse of the following matrix.
233122111

Open in App
Solution

As, A=IA,
233122111=100010001A
And we know that I=A1A.
So, by row transformation we will try to convert LHS into I

[R2R2+R3andR1R12R3]

011011111=102011001A

[R2R2+R1]

011000111=102212001A
Since, second row of the matrix A on LHS is containing all zeroes, so we can say that every inverse of matrix A does not exist.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finding Inverse Using Elementary Transformations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon