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Question

If pressure of CO2 (real gas) in a container is given by P = RT2Vba4V2 then mass of the gas in container is

A
11 gm
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B
22 gm
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C
33 gm
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D
44 gm
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Solution

The correct option is B 22 gm

Vander wal's gas equation for μ mole of real gas
(P + μ2αV2)(V - μb) = μRT P = μRTVμbμ2V2
on comparing the given equation with this standard equation we get μ=12. Hence μ = mM mass of gas
m = μM = 12×44 = 22gm


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