If ray OC stands on line AB such that Angle AOC = Angle BOC then show that
Angle BOC= 90˚

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Solution

AB is a straight line in which OC is standing means OC is perpendicular To AB.
So
OF perpendicular to AB then,
O is the M.p of AB, AngLe BOC=Angle AOC
BOC=90 degree becoz oc perpendicular to AB.
Boc+Aoc=180 (linear pair).
2AOC=180degree
AOC=180/2=90degree.
then angleBOC =90 degree.
hence proved.

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If ray OC stands on line AB such that Angle AOC = Angle BOC then show that Angle BOC= 90˚

AB is a straight line in which OC is standing means OC is perpendicular To AB. So OF perpendicular to AB then, O is the M.p of AB, AngLe BOC=Angle AOC BOC=90 degree becoz oc perpendicular to AB. Boc+Aoc=180 (linear pair). 2AOC=180degree AOC=180/2=90degree. then angleBOC =90 degree. hence proved.

If ray OC stands on line AB such that Angle AOC = Angle BOC then show that
Angle BOC= 90˚

AB is a straight line in which OC is standing means OC is perpendicular To AB.
So
OF perpendicular to AB then,
O is the M.p of AB, AngLe BOC=Angle AOC
BOC=90 degree becoz oc perpendicular to AB.
Boc+Aoc=180 (linear pair).
2AOC=180degree
AOC=180/2=90degree.
then angleBOC =90 degree.
hence proved.