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Question

If secθ+tanθ=p, then find the value of secθtanθ

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Solution

Given secA + tan A = p

Recall the identity, sec2A – tan2A = 1

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1

∴ (secA – tanA) = 1/p

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