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Question

If secA = x+1x,prove that secA×tanA=2x or 12×.

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Solution

sec2A=1+tan2Ax2+12+1(16x2)=1+tan2Ax212+1(16x2)=tan2A±[x1(4x)]=tanAsecA+tanA=x+1(4x)±(x1(4x))=2xor1(2x)

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