If sin−1(sin(2x2+41+x2))<π−3
The value of x for which sin−1{sin(2x2+41+x2)}<π−3 is
Find the value of x so that; (i) (34)2x+1=((34)3)3(ii) (25)3×(25)6=(25)3x(iii) (−15)20÷(−15)15=(−15)5x(iv) 116×(12)2=(12)3(x−2)