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Question

If sin1x+sin1y+sin1z=π2, then x2+y2+z2+2xyz=

A
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B
1
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C
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D
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Solution

The correct option is B 1
Given Expression
cos1(1x2)+cos1(1y2)=π2sin1z
[(1x2)(1y2)]xy=z(1x2)(1y2)=(xy+z)2x2+y2+z2+2xyz=1


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