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Question

If sin2θ2sinθ1=0is to be satisfied for exactly 4 distinct values of θ[0,nπ],nN, then the least value of n is:

A
2
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B
6
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C
4
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D
15
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Solution

The correct option is C 4
sin2θ2sinθ1=0
sin2θ2sinθ(sin2θ+cos2θ)=0
cos2θ2sinθ=0
2cosθsinθ2sinθ=0
2sinθ(cosθ1)=0
sinθ=0 or cosθ=1
θ=0,π,2π,3π.... θ=0,2π,4π.....
θ[0,4π]
Least value of n is 4.

1362078_1127703_ans_f51957949f4c4d098aeedc43704bbd39.jpg

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