If sin A and sin B of a - ABC satisfy c 2 x 2- c a - b x - ab -0 then the triangle isA- isoscelesB- equilateralC- right angledD- acute angled

The correct option is C right angled sin A+sin B=c(a+b)/c^2=a+b/c sin A sin B=ab/c^2 ∴ sin A=a/2R, sin B=b/2R ∴a+b/2R=a+b/c ∴ c=2R ∴ right angled ...

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Global Maxima

If sin A and ...

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If $s i n A$ and $s i n B$ of a $Δ A B C$ satisfy $c^{2} x^{2} - c (a + b) x + a b = 0$ then the triangle is

equilateral

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isosceles

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right angled

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acute angled

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