If sin A -8-17- find the value of A cos A -cosec A cos A-A- 6-23-815-15D- 10-8-23-8

The correct option is D sin A = 8/17 cosec A = 17/8 cosA = √(1 sin^2A) = √(1 64/289) = √(225/289) = 15/17 secA = 17/15 secA cosA + cosecA cosA = 17/15× ...

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Standard X

Mathematics

Trigonometric Ratios

If sin A =8/1...

Question

If $s i n A = \frac{8}{17}$ , find the value of secA cosA + cosecA cosA.

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Solution

The correct option is D

$s i n A = \frac{8}{17}$

$c o s e c A = \frac{17}{8}$

$c o s A = \sqrt{1 - s i n^{2} A}$

$= \sqrt{1 - \frac{64}{289}} = \sqrt{\frac{225}{289}} = \frac{15}{17}$

$s e c A = \frac{17}{15}$

$s e c A c o s A + c o s e c A c o s A = \frac{17}{15} \times \frac{15}{17} + \frac{17}{8} \times \frac{15}{17}$

$= 1 + \frac{15}{8}$

$= \frac{23}{8}$

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If sinA=817, find the value of secA cosA + cosecA cosA.

The correct option is D sinA=817 cosecA=178 cosA=√1−sin2A =√1−64289=√225289=1517 secA=1715 secAcosA+cosecAcosA=1715×1517+178×1517 =1+158 =238

If $s i n A = \frac{8}{17}$ , find the value of secA cosA + cosecA cosA.