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Question

If sin A = n sin B, then nāˆ’1n+1 tan A+B2 =


A

sin (AB2)

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B

tan (AB2)

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C

cot (AB2)

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D

cos (AB2)

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Solution

The correct option is B

tan (AB2)


We have sin A = n sin B n1 = sinAsinB

n1n+1 sinAsinBsinA+sinB = 2cosA+B2sinAB22sinA+B2cosAB2

= tan AB2 cot A+B2

n1n+1 tan(A+B2) = tan AB2.


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