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Question

If sinθ+sin2θ=1, then cos4θ+cos2θ1=

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  1. 2

  2. 1

  3. 0

  4. -1


Solution

The correct option is C

0


sinθ+sin2θ=1.....(i)

1sin2θ=sinθ ....(ii)

Thus, cos4θ+cos2θ1

=(cos2θ)2sin2θ

=(1sin2θ)2sin2θ

=(sinθ)2sin2θ.... from (ii)

=sin2θsin2θ

=0

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