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Question

If sin x +sin 2 x =1, then write the vaue of cos12x+3cos10x+3cos8x+cos6x


Solution

sinx+sin2x=1

sinx=1sin2x=cos2x

cos12x+3cos10x+3cos8x+cosx

=sin6x+3sin5x+3sin4x+sin3x

=(sinx+sin2x)3

=1


Mathematics
RD Sharma
Standard XI

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