Question

# If sin x + sin y = $\sqrt{3}$ (cos y − cos x), then sin 3x + sin 3y = (a) 2 sin 3x (b) 0 (c) 1 (d) none of these

Solution

## We have, sin x + sin y = $\sqrt{3}$ (cos y − cos x) $\mathrm{Case}-\mathrm{I}$ ${\mathrm{sin}}3x+\mathrm{sin}3y=\mathrm{sin}\left(-3y\right)+\mathrm{sin}3y=-\mathrm{sin}3y+\mathrm{sin}3y=0$ MathematicsRD Sharma XI (2015)Standard XI

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More