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Question

If sinx+siny=3(cosycosx), then the value of sin3xsin3y is
  1. 1
  2. 1
  3. 0
  4. 3


Solution

The correct option is C 0
sinx+siny=3(cosycosx)
sinx+3cosx=3cosysiny
Put 1=rcosθ and 3=rsinθ
rcosθsinx+rsinθcosx=rsinθcosyrcosθsiny
sin(x+θ)=sin(θy)
x+θ=θy
x=y
Therefore, sin3xsin3y=1

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