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Question

If sin2θcos2θ=14, then the values of θ which satisfy the equation is

A
θ=nπ8+(1)n(π48), nZ
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B
θ=nπ4+(1)n(π24), nZ
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C
θ=nπ2+(1)n(π24), nZ
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D
θ=nπ4+(1)n(π12), nZ
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Solution

The correct option is B θ=nπ4+(1)n(π24), nZ
sin2θcos2θ=14
2sin2θcos2θ=12
sin4θ=12
4θ=nπ+(1)n(π6)
θ=nπ4+(1)n(π24), nZ


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