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Question

If sinθ=35, where θ(0,π2),then (sec2θ+tan2θ) is 17k.
then the value of k is .

A
18
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B
116
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C
132
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Solution

The correct option is A 18
Given sinθ=35=(opposite)(hypotenuse)adjacent side=5232=4.
Now, we can write
secθ=54 and tanθ=34.
sec2θ+tan2θ=2516+916sec2θ+tan2θ=3416=178.


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