If some coins each of diameter $1.5 c m$ and thickness $0.2 c m$ are melted and a right circular cylinder of height $10 c m$ and diameter $4.5 c m$ is made, then find the number of coins required to make the right circular cylinder

336

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450

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512

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545

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Solution

The correct option is C $450$
Number of coins $= \frac{V o l u m e o f c y l i n d e r}{V o l u m e o f 1 c o i n} = \frac{π R^{2} H}{π r^{2} h} = \frac{{(\frac{4.5}{2})}^{2} \times 10}{{(\frac{1.5}{2})}^{2} \times 0.2}$
$= 450$

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and diameter

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Q. Find the number of coins, 1.5 cm is diameter and 0.2 cm thick, to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

Q. The number of coins 1.5 cm in diameter and 0.2 cm thick to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm is
(a) 540
(b) 450
(c) 380
(d) 472

The number of coins of $1.5 c m$ in diameter and $0.2 c m$ thick, to be melted to form a right circular cylinder of height $10 c m$ of diameter $4.5 c m$ is

(a) $540$ (b) $450$ (c) $380$ (d) $472$

Q. How many coins of diameter 1.5 cm and 0.2 cm thickness are formed by melting a right circular cylinder of height 8 cm and diameter 6 cm?

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If some coins each of diameter 1.5 cm and thickness 0.2 cm are melted and a right circular cylinder of height 10 cm and diameter 4.5 cm is made, then find the number of coins required to make the right circular cylinder

The correct option is C 450Number of coins =VolumeofcylinderVolumeof1coin=πR2Hπr2h=(4.52)2×10(1.52)2×0.2 =450

If some coins each of diameter $1.5 c m$ and thickness $0.2 c m$ are melted and a right circular cylinder of height $10 c m$ and diameter $4.5 c m$ is made, then find the number of coins required to make the right circular cylinder

The correct option is C $450$
Number of coins $= \frac{V o l u m e o f c y l i n d e r}{V o l u m e o f 1 c o i n} = \frac{π R^{2} H}{π r^{2} h} = \frac{{(\frac{4.5}{2})}^{2} \times 10}{{(\frac{1.5}{2})}^{2} \times 0.2}$
$= 450$