Question

The area of the figure formed by joining the mid points of the adjacent sides of a thombus with diagonals 16 cm and 12 cm is

28cm2

48cm2

96cm2

24cm2

Solution

The correct option is **B**

48cm2

In rhombus ABCD,

P,Q,R and S are the mid points of sides AB, BC, CD and DA respectively and are joined in order to get a quad. PQRS.

Diagonals AC = 16 cm and BD = 12 cm

∴ Area of PQRS=12 area rhombus ABCD

=12×AC×BD2=14×16×12cm2=48cm2

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