If $\sqrt{2} = 1.4142$ , then the square of $14.142$ should approximately be?

$20$

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$200$

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$2000$

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$2500$

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Solution

The correct option is B
$200$

$\sqrt{2} = 1.4142$ (Given)

Multiply both sides by $10$

$10 \times \sqrt{2} = 14. 142$

$\sqrt{100 \times 2} = 14.142$

Squaring both sides, we get the square of $14.142$ to be approximately equal to $200$ .

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Similar questions

If $\sqrt{2} = 1.4142$ , then $\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}$ is equal to

\sqrt{2} = 1.4142

\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}

If $\sqrt{2} = 1.4142$ , then the square of $14.142$ should approximately be?

If $\sqrt{2} = 1.4142$ then $\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}} = ?$

\sqrt{2}

\frac{\sqrt{2} - 1}{\sqrt{2} + 1}

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