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Question

If 512i+512i=z, then principal value of argz can be

A
π4
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B
π4
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C
3π4
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D
3π4
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Solution

The correct options are
A π4
B π4

C 3π4
D 3π4
512i=(32i)2=±(32i)
512i=(23i)2=±(23i)
512i+512i=1i, 5+5i, 55i, 1+i
Therefore, the principal values of argz are 3π4,3π4,π4,π4

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