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Question

If a+ib== x + iy, then possible value of aib is 



A

x2+y2

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B

x2+y2

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C

x + iy

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D

x - iy

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E

x2y2

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Solution

The correct option is B

x - iy


a+ib=x+iy

Squaring on both sides, we get,

a+ib=x2+(iy)2+2ixy a+ib=(x2y)2+2ixy a=(x2y2)and b = 2xy aib=(x2y2)2ixy aib=x2+i2y22ixy   [ i2=1]

Taking square root on both sides, we get :

aib=xiy


Mathematics
RD Sharma
Standard XI

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