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Question

If sum of the roots of the equation ax2+bx+c=0 is equal to the sum of their squares, then

A
2ac=ab+c
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B
2ac=b(a+b)
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C
a2+b2=c2
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D
a2+b2=a+b
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Solution

The correct option is A 2ac=b(a+b)
Sum of the roots of the equation ax2+bx+c=0 is equal to the sum of their squares.
Let α,β be the roots.
α+β=ba and αβ=ca
α+β=α2+β2
ba=(ba)22(ca)
=b22aca2
ab=b22ac
2ac=b(a+b)
Hence, option B.

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