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Question

If sum of three numbers is 4, sum of their squares is 14, sum of their cubes is 34 and their products is 6, then sum of products of two numbers at a time is 
  1. 1
  2. 1
  3. 27
  4. 2


Solution

The correct option is B 1
As we know that
a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)
343(6)=4(14ab)
ab=1

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