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Question

If $$T_1, T_2$$ and $$T_3$$ are the time periods of a given simple pendulum on the surface of the earth, at a depth $$h$$ in a mine and at an altitude $$h$$ above the earth's surface respectively, then


A
T1=T2=T3
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B
T2<T1>T3
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C
T2>T1<T3
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D
T1>T2>T3
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Solution

The correct option is B $$T_2 > T_1 < T_3$$
As  we go inside a mine $$g$$ decreases and also for height $$h$$ , $$g$$ decreases.
as  $$T  \alpha \dfrac{1}{\sqrt{g}}$$
$$ \therefore  \ \ T_{2}>T_{1},$$   and   $$T_{3}>T_{1}$$. But  $$T_{2}>T_{3}$$  as change in $$g$$ for depth is more than that for height.

$$\therefore T_{2}>T_{1}<T_{3}$$

Physics

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