If T is the surface tension of a liquid, the energy needed to break a liquid drop of radius R into 64 drops is
The correct option is D 12πR2T
Radius of larger drop =R
Surface Tension =T
Number of smaller drop, n=64
Let us suppose, radius of smaller drop is r.
As volume of liquid will be same.
Volume of larger drop = Volume of n smaller drops
We know that, change in energy = surface tension × change in surface area
[ from (1) and surface area =4πr2 ]