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Question

If Tn=3n1 of an A.P., then 
  1. a=2
  2. d=3
  3. T5=15
  4. S3=15


Solution

The correct options are
A a=2
B d=3
D S3=15
Given : Tn=3n1
Now,
a=T1=3×11=2   (i)a+d=T2=3×21=5   (ii)a+2d=T3=3×31=8   (iii)a+3d=T4=3×41=11   (iv)
Therefore, a=2,d=3
Now,
S3=T1+T2+T3S3=2+5+8=15

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