If tan A -3-4- then find the value of Sin A -Cos A -Sin A -Cos A-A- -7

The correct option is A 7Given, nbsp; tan A=3/4 Now, nbsp; Sin A + Cos A/Sin A Cos A Dividing the numerator and denominator by Cos A =Sin A/Cos A+1/Si ...

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Standard X

Mathematics

Trigonometric Ratios of a Right Triangle

If tan A =3/4...

Question

If $t a n A = \frac{3}{4}$ , then find the value of $\frac{S i n A + C o s A}{S i n A - C o s A}$ .
-7

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Solution

The correct option is A -7
Given,
$t a n A = \frac{3}{4}$

Now,
$\frac{S i n A + C o s A}{S i n A - C o s A}$

Dividing the numerator and denominator by $C o s A$

$= \frac{\frac{S i n A}{C o s A} + 1}{\frac{S i n A}{C o s A} - 1}$
$= \frac{t a n A + 1}{t a n A - 1}$
$= \frac{\frac{3}{4} + 1}{\frac{3}{4} - 1}$
$= \frac{\frac{7}{4}}{\frac{- 1}{4}}$
$= - 7$

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If tan A=34, then find the value of Sin A + Cos ASin A − Cos A.-7

The correct option is A -7Given, tan A=34 Now, Sin A + Cos ASin A − Cos A Dividing the numerator and denominator by Cos A =Sin ACos A+1Sin ACos A−1 =tan A +1tan A − 1 =34+134−1 =74− 14 =− 7

If $t a n A = \frac{3}{4}$ , then find the value of $\frac{S i n A + C o s A}{S i n A - C o s A}$ .
-7