If tan -sin - m and tan -sin - n- Show that m - 2- n - 212-16 mn-

(m² n²)² = gt;(tanA + sinA)² (tan A sinA)²² = gt; 4tanAsinA² = gt;16tan²A sin²A RHS:16(tanA+sinA)(tanA sinA) = gt;16 ( tan²A sin²A) = gt;16 (s ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Standard Values of Trigonometric Ratios

If tan +sin =...

Question

If tan  + sin  = m and tan  - sin  = n , Show that (m^2 – n^2 )^2 = 16 mn .

Open in App

Solution

Suggest Corrections

Similar questions

tan A + sin A = m

tan A - sin A = n

(m^{2} - n^{2})^{2} = 16 m n

\tan θ + \sin θ = m a n d \tan θ - \sin θ = n, s h o w t h a t m^{2} + n^{2} = 4 \sqrt{m n} .

tan A + sin A = m

tan A - sin A = n

m^{2} - n^{2} = 4 \sqrt{m n}

If $t a n θ + s i n θ = m$ and $t a n θ - s i n θ = n$

Show that $m^{2} - n^{2} = 4 \sqrt{m n}$ [4 MARKS]

Join BYJU'S Learning Program