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Question

If tanθ=125. find the value of 1+sinθ1sinθ

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Solution

we have,

tanθ=ab

c=a2+b2

sinθ=ac

Given,

tanθ=125

c2=122+52

c=13

sinθ=1213

1+sinθ1sinθ=1+121311213

=251=25

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