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Question

If the 10th term of an AP is 52 and 17th term is 20 more than its 13th term, find the AP.
 


Solution

given, a10=52           
         a+9d=52 ...........(1)
 also,    a17=20+a13
       a+16d=20+a+12d
        16d12d=20
         4d=20
           d=5
   putting the value of d in eq. (1), we get,
           a+9(5)=52
           a+45=52
             a=7
    hence, the required AP is 7,12,17,.........


Mathematics
Secondary School Mathematics X
Standard X

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