Question

# If the absolute temperature of an ideal gas having volume V $$cm^3$$ is doubled and the pressure is reduced to half, the final volume of gas will be?

A
0.25V
B
0.50V
C
2V2
D
4V

Solution

## The correct option is D $$4V$$Let $$T_1=T$$$$\therefore T_2=2T$$Let $$P_1=P$$$$\therefore P_2=P/2$$Given that, $$V_1=Vcm^3$$ $$P_1V_1=nRT_1$$$$P_2V_2=nRT_2$$$$\therefore \dfrac{P_1}{P_2}\times \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$$$$\therefore (2)\left(\dfrac{V}{V_2}\right)=\dfrac{1}{2}$$$$\therefore V_2=4Vcm^3$$Hence, option $$D$$ is correct.Physics

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