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B
The acceleration of the masses will be (a0+g)
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C
The tension in the string will be MmM+m(g+a0)
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D
Tension in the string will be zero.
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Solution
The correct option is D Tension in the string will be zero. Using the concept of pseudo force in the frame of elevator we have,
FBDs of both the blocks are as shown
Let acceleration of the masses w.r.t pulley be a.
For M:Mg−T−Ma0=Ma;
Foro m:T+ma0−mg=ma; ⇒a=M−mM+m(g−a0)⇒T=2MmM+m(g−a0) ∵a0=g ⇒a=0andT=0