Question

If the addition of numbers 2A and 33 gives 5B, where A and B are digits then find A and B. Given that number 2A is divisible by 10.

• A. A = 0, B = 0
• B. A = 0, B = 4
• C. A = 4, B = 0
• D. A = 0, B = 3

Answer 1

The correct option is D

A = 0, B = 3

Since 2A is divisible by 10, number 2A should have 0 as the last digit. So, A = 0.
Now 2A becomes 20 and 20+33=53
Hence, 5B = 53 and B=3