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Question

If the angle between two lines represented by 2x2+5xy+3y2+7y+4=0 is tan−1m, then m is equal to.

A
15
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B
1
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C
75
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D
7
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Solution

The correct option is A 15
2x2+5xy+3y2+7y+4=0
Comparing above eqn. with general eqn. of pair of straight line
ax2+2hxy+by2+2gx+2fy+c=0
We get a=2, h=52, b=3, g=0, f=72 and c=4
Angle b/w pair of straight lines is
θ=tan1[2h2aba+b]
tan1m=tan1⎢ ⎢ ⎢ ⎢225462+3⎥ ⎥ ⎥ ⎥
m =25245
m=15

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