Question

If the area of an isosceles right triangle is 8cm, what is the perimeter of the triangle. 8+√2cm2   8+4√2cm2   4+8√2cm2   12+√2cm2

Solution

The correct option is B 8+4√2cm2   Let base = x ABC an isosceles right triangle, which has 2 sides same  ⇒Height=x Area = 8 cm  (Given) ∴Area=12×Base×Height 8cm=12×x×x x2=16 ⇒x=√16=4cm (Where x = base and height) Now, by Pythagoras Theorem AC2=AB2+BC2 =42+42 = 16+16= 32 cm AC=√32 ⇒AC=4√2cm Perimeter of an isosceles triangle = AB+BC+CA = 4+4+4√2cm = 8+4√2cm

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