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Question

If the area of an isosceles right triangle is 8cm, what is the perimeter of the triangle.


  1. 8+2cm2
     

  2. 8+42cm2
     

  3. 4+82cm2
     

  4. 12+2cm2
     


Solution

The correct option is B

8+42cm2
 


Let base = x
ABC an isosceles right triangle, which has 2 sides same 
Height=x


Area = 8 cm  (Given)
Area=12×Base×Height
8cm=12×x×x
x2=16
x=16=4cm
(Where x = base and height)
Now, by Pythagoras Theorem
AC2=AB2+BC2
=42+42
= 16+16= 32 cm
AC=32
AC=42cm
Perimeter of an isosceles triangle
= AB+BC+CA
= 4+4+42cm
= 8+42cm

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