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Byju's Answer
Standard XII
Mathematics
Equation of Circle with (h,k) as Center
If the area o...
Question
If the area of the circle
x
2
+
y
2
+
4
x
+
2
y
+
k
=
0
is
5
π
square
c
m
, then
k
=
?
A
−
20
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B
20
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C
±
20
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D
0
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Solution
The correct option is
D
0
x
2
+
y
2
+
4
x
+
2
y
+
k
=
0
x
2
+
4
x
+
2
2
−
2
2
+
y
2
+
2
y
+
1
2
−
1
2
+
k
=
0
(
x
+
2
)
2
+
(
y
+
1
)
2
−
5
+
k
=
0
(
x
+
2
)
2
+
(
y
+
1
)
2
=
5
−
k
(
x
+
2
)
2
+
(
y
+
1
)
2
=
(
√
5
−
k
)
2
Comparing with the standard form of equation of circle
(
x
−
h
)
2
+
(
y
−
k
)
2
=
l
2
, we get
r
=
√
5
−
k
Area of circle
=
5
π
c
m
2
π
r
2
=
5
π
π
(
5
−
k
)
=
5
π
5
−
k
=
5
5
−
5
=
k
k
=
0
Suggest Corrections
0
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Q.
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Equation of Circle with (h,k) as Center
Standard XII Mathematics
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