If the area of the given triangle given below is 20, what are the co-ordinates of point C?

(0, \frac{40}{a})

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(a^{2} + b^{2}, 0)

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(\frac{20}{b}, 0)

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(\frac{40}{b}, 0)

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Solution

The correct option is D $(\frac{40}{b}, 0)$
Let the cordinate of 'c' be (d, 0)
$\Rightarrow \frac{1}{2} ∣ ∣ ∣ ∣ \begin{matrix} 0 & 0 & 1 a & b & 1 d & 0 & 1 \end{matrix} ∣ ∣ ∣ ∣ = 20 \Rightarrow b d = 40$
$\Rightarrow d = \frac{40}{b}$

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If the area of the given triangle given below is 20, what are the co-ordinates of point C?

The correct option is D (40b,0)Let the cordinate of 'c' be (d, 0)⇒12∣∣ ∣∣001ab1d01∣∣ ∣∣=20⇒bd=40⇒d=40b

The correct option is D $(\frac{40}{b}, 0)$
Let the cordinate of 'c' be (d, 0)
$\Rightarrow \frac{1}{2} ∣ ∣ ∣ ∣ \begin{matrix} 0 & 0 & 1 a & b & 1 d & 0 & 1 \end{matrix} ∣ ∣ ∣ ∣ = 20 \Rightarrow b d = 40$
$\Rightarrow d = \frac{40}{b}$