Question

If the area of the square is $(x^2-2xy+y^2)m^2$, then find the side of the square.

• A. (x + y) m
• B. (x - y) m
• C. $(x^2-x+y)$ m
• D. (2x - y) m

Answer 1

The correct option is B (x - y) m

Given: Area of the square $=(x^2-2xy+y^2)m^2$.
Let the side of the square be 'a' m.
Area of the square $=a\times a$
$\Rightarrow a^2=(x^2-2xy+y^2)$
This is in the form of $(a-b{)}^2=a^2+b^2-2ab$ where, $a=x$ and $b=y$.
$\Rightarrow$ $(x-y{)}^2=a^2$

Taking square root on both side, we get $\sqrt{(x-y{)}^2}=\sqrt{a^2}$
$\Rightarrow a=x-y$
Hence, the side of the square is $(x-y)$ m.