CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the area of trapezium ABCE is 35 cm2, and CE = 8 cm, AE = 5 cm, find the area of BDC.

A
5 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5 cm2
Area of triangle
= Area of trapezium ABCE
- Area of rectangle ABDE

Area of trapezium ABCE
= 12×(Sum of parallel sides)×height
35 = 12×(AB+CE)×AE
35 = 12×(AB+8)×5
35×25 = AB+8 = 7×2 = 14
AB+8 = 14
AB = 14-8 = 6 cm

Area of rectangle ABDE
= length×breadth
= AB×AE = 6×5 = 30 cm2

Area of triangle = 35 - 30 = 5 cm2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadrilaterals
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon