If the atomic weight of an element is $23$ times that of the lightest element and it has $11$ protons, then it contains:

11

protons,

23

neutrons,

11

electrons

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11

protons,

11

neutrons,

11

electrons

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11

protons,

12

neutrons,

11

electrons

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11

protons,

11

neutrons,

23

electrons

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Solution

The correct option is C $11$ protons, $12$ neutrons, $11$ electrons
Number of electron = number of proton
Hence,
number of electrons $= 11$
and number of protons $= 11$
The lightest element is hydrogen which has atomic weight 1.
Thus, an atomic weight of the element will be 23.
number of neutron = mass number - atomic number
$= 23 - 11 = 12$

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If the atomic weight of an element is 23 times that of the lightest element and it has 11 protons, then it contains:

If the atomic weight of an element is $23$ times that of the lightest element and it has $11$ protons, then it contains: