If the circle x2-y2-4x-8y-16-0 rolls up the -an gent to it at -2-3 -3- by 2 units -assumes x-axis as horizontal- - then the centre of the circle in the position i

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Latus Rectum

If the circle...

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If the circle x2+y2-4x-8y+16=0 rolls up the †an gent to it at (2+\sqrt{3 },3) by 2 units (assumes x-axis as horizontal) , then the centre of the circle in the position i

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x^{2} + y^{2} - 4 x - 8 y + 16 = 0

(2 + \sqrt{3}, 3)

2

x^{2} + y^{2} - 4 x - 8 y + 16 = 0

(2 + \sqrt{3}, 3)

2

x^{2} + y^{2} - 4 x - 8 y + 16 = 0

x -

(2 + \sqrt{3}, 3)

2

x^{2} + y^{2} + 2 a x + 2 b y + c = 0,

a^{2} + 8 b + c

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\sqrt{3} y - x = 0

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